Promotion Play – Part 1
Peter's Problem World with FIDE Master of Chess
Composition
Peter Wong

Note that Peter's articles, follow a chess problem
convention in using ‘S’ to represent the knight
(from the German word,
Springer). ‘N’ is reserved for a fairy piece called the nightrider.
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Pawn promotion, as one of the special moves
in chess, is a popular device that composers often use as the focus of a
problem.
Rendering promotion as the
theme usually means that the move is set to take place in multiple
variations, as a recurring motif. The play may emphasise the need
to carefully select the right promoted piece, with underpromotions a
favoured feature.
Sometimes promotion to a variety of piece
types constitutes the main point, as in for instance the
Allumwandlung theme, the subject of an earlier Problem World instalment.
We will here concentrate on
directmates showing this special pawn move, and in the next article
examine its appearance in
helpmates. |
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85. Henry
Bettmann
Good Companions
1923
       
       
       
       
       
       
       
       
Mate in 2 |
When White gives mate in a problem by
promoting a pawn, we need to distinguish only between the choice of
queen and knight as the new piece, because the queen encompasses the
power of rook and bishop.
Problem 85 illustrates how a
single pawn can give the maximum six different mates by promoting in
turn to a queen and a knight on three squares.
The
key is 1.Rd7!, which threatens 2.cxb8(S), 2.c8(Q), and
2.cxd8(S). These mates are separately forced in the following
lines, in addition to three other promotions: 1…Kxc6 2.cxb8(S),
1….Sxc6 2.cxb8(Q), 1…Kxa7 2.c8(S), 1…Se6 2.c8(Q),
1…Rc8 2.cxd8(S), and 1…Kc8 2.cxd8(Q).
In some variations, the queen-promotion
mate can be replaced by a rook- or bishop-promotion, but such
dual mates are not regarded as a flaw, unlike other cases of
non-unique White play. |


If Black
promotes in a
two-mover, again only the choice of queen or knight is relevant (though
in some longer directmates, Black may pick a rook or a bishop in attempting
to induce stalemate).
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Problem 87 uses two black
promotions as the thematic defences to generate the
Zagoruiko scheme.
In the set play, White exploits the
self-blocks of the promotion moves by 1…e1(Q) 2.Rd4, and 1…e1(S)
2.Be3.
Virtual play arises after the
try 1.Se3? (waiting), giving 1…e1(Q) 2.Qc2, and 1…e1(S) 2.Sf1, but
1…Bb2!
refutes the try by pinning the knight (1…Ba3 2.Se4).
The
actual play incorporates a third pair of mates in answer to the
promotions: 1.Sf2! (waiting), 1…e1(Q) 2.Qd3, and
1…e1(S) 2.Sfe4.
The key grants a
flight on e3, and leads to good
by-play, 1…Ke3 2.Qd3, 1…Ke1 2.Qxc1, and 1…B-any
2.Sfe4. |
87. Ottavio
Stocchi
L’Italia Scacchistica
1958
       
       
       
       
       
       
       
       
Mate in 2 |

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In Problem 88, the white rook can
threaten mate on the third rank by moving east, but the two black pawns
seem capable of defending any of the third-rank squares by promoting to
a queen or a knight.
To deliver mate in four, White takes
advantage of the fact that once a black pawn has promoted to one type of
piece, it loses the option to become another one. Consider 1.Rc8?
which, if played immediately, is defeated by 1…e1(Q)!
To preclude this defence, White can force
the pawn to promote to a knight instead, with 1.Rd8? e1(S) 2.Rc8, but
unfortunately 2…f1(Q)+! now refutes. Therefore White must take an
additional step to induce the f-pawn to promote to the wrong piece as
well: 1.Rg8! f1(S) 2.Rd8 d1(S) 3.Rc8, and now 4.Rc3 is
unstoppable.
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88. Erwin
Guttmann
Miniatures Stratégiques
1935
       
       
       
       
       
       
       
       
Mate in 4 |
White’s strategy, to counter an adequate
promotion defence by provoking Black to promote to a different type of
piece, thereby ruling out the initial choice, is called the Holst
theme and it is shown twice here.

Problem
89 is a marvellous demonstration of a triple-underpromotion by White.
The black king is in a fortress-like position, which cannot be breached even
if White gains a queen on f8. A potential stalemate also looms, when
the three mobile black pawns have exhausted their moves.

Problem 90 is for you to
solve. The best play involves subtle promotion choices on both sides.
90. Allan
Werle
Tidskrift för
Schack
1945
       
       
       
       
       
       
       
       
Mate in 4
Solution
to Problem 90 (To display, hold down your mouse button and select the
text below)
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>The obvious 1.e8(Q)?
is refuted by 1…d1(S)+!
2.Kg3 Se3 3.Qxe3
stalemate (or 2.Kf1 Se3+
3.Qxe3 Kh2 4.?). Only
1.e8(R)! solves in four
moves, 1…d1(S)+ 2.Kg3
Se3 3.Rxe3 Kg1 4.Re1.>
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Chess Composition
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